0580.C4.1.23 — trapezium.: past paper questions

Real questions on 0580.c4.1.23 — trapezium.

The newest 6 of 6 written questions. Open one to see it on the real paper.

1. 0580/12 · May/June 2026 · Q15[2]
   15 Write down two geometrical properties of a parallelogram. 1 2See it on the paper →
2. 0580/13 · May/June 2025 · Q14[2]

   2-mark question — its maths and diagrams are best seen on the paper.

   See it on the paper →
3. 0580/42 · May/June 2025 · Q4[2]
   [Diagram: A trapezium $ABCD$ with parallel sides $DC$ and $AB$. $DC=10\text{ cm}$, $AB=12\text{ cm}$. A dashed perpendicular line from $D$ to the extension of $AB$ has length $8\text{ cm}$. The diagram is marked "NOT TO SCALE".] $ABCD$ is a trapezium. Work out the area of the trapezium.See it on the paper →
4. 0580/12 · February/March 2024 · Q19[3]
   19 [Diagram: Two circles side-by-side, not to scale. The left circle has a dashed radius line labelled $7\text{ cm}$. The right circle has a dashed radius line labelled $R\text{ cm}$. The text "NOT TO SCALE" is to the right.] The diagram shows a small circle with radius $7\text{ cm}$ and a large circle with radius $...See it on the paper →
5. 0580/12 · February/March 2024 · Q23[2]
   [Diagram: Two triangles, NOT TO SCALE. Triangle $ABC$ with side $AB=h$ cm and side $AC=118.9$ cm. Triangle $DEF$ with side $ED=97.5$ cm and side $DF=159.9$ cm.] Triangle $ABC$ is mathematically similar to triangle $DEF$. Calculate the value of $h$. $h=$See it on the paper →
6. 0580/11 · October/November 2023 · Q20[2]
   20 [Diagram: A trapezium with a top parallel side of length $8\text{ cm}$, a bottom parallel side of length $14\text{ cm}$, and a perpendicular height of $6\text{ cm}$ indicated by a dashed line with a right-angle symbol. The diagram is labelled "NOT TO SCALE".] Find the area of this trapezium.See it on the paper →

What examiners said

More able candidates were able to give the correct answer. Some gained 1 mark for correctly substituting into the equation but were unable to rearrange it correctly. Others did not equate their substitution to 42.

— Examiner report, May/June 2025, 0580/13 Q14 (Cambridge)

A large majority of candidates used the correct formula for the area of a trapezium and gave a correct answer. Although it was possible to split the shape up into triangles to obtain the correct answer, many who tried this were unsuccessful. Some used incorrect formulae for the trapezium, including 1 1 12 10 8 = 480 or 12 8 = 48. 2 2

— Examiner report, May/June 2025, 0580/42 Q4 (Cambridge)

This was a demanding question due to several stages to work through. However, there were a number of fully correct responses. A basic error often seen was working with the formula for circumference instead of area. Rounding in calculations often caused a mark to be lost. The in the calculations was correctly eliminated by some of the more able candidates but this was not essential. Candidates appr...

— Examiner report, February/March 2024, 0580/12 Q19 (Cambridge)