0580.E2.5.01 — 3x + 4 = 10.: past paper questions

Real questions on 0580.e2.5.01 — 3x + 4 = 10.

The newest 7 of 7 written questions. Open one to see it on the real paper.

1. 0980/21 · October/November 2025 · Q8[2]
   The cost of one orange is $t$ cents. The cost of one apple is $w$ cents. The total cost of 3 oranges and 1 apple is 51 cents. The total cost of 6 oranges and 5 apples is 129 cents. Use simultaneous equations to find the value of $t$ and the value of $w$. You must show all your working.See it on the paper →
2. 0980/42 · May/June 2024 · Q7a[2]
   (a) Solve $3x-8=6-4x$.See it on the paper →
3. 0980/42 · May/June 2024 · Q7b[2]
   (b) Factorise fully $10a^2+5a$.See it on the paper →
4. 0980/42 · May/June 2023 · Q3a(i)[3]
   The diagram shows a right-angled triangle $ABC$. [Diagram: A right-angled triangle $ABC$ with the right angle at $A$. The vertical side $AC$ is labelled $(x+3)\text{ cm}$. The horizontal side $AB$ is labelled $(2x+5)\text{ cm}$. The text "NOT TO SCALE" is present.] (a) (i) The area of the triangle is $60{\text{ cm}}^2$....See it on the paper →
5. 0980/42 · May/June 2023 · Q3a(ii)[3]
   [Diagram: Right-angled triangle $ABC$ with right angle at $A$. Side $AC$ is labelled $(x+3)\text{ cm}$. Side $AB$ is labelled $(2x+5)\text{ cm}$. Text "NOT TO SCALE" is present.] The diagram shows a right-angled triangle $ABC$. (ii) Solve by factorisation. $2x^2+11x-105=0$See it on the paper →
6. 0980/41 · October/November 2022 · Q3c(i)[4]
   (c) Solve the equations. (i) $3(3-x)-\frac{2(x+2)}{5}=1$See it on the paper →
7. 0980/31 · October/November 2021 · Q3d(ii)[3]
   360 people go on a school trip to one of four places. Some of the information is shown in the table. | | Adventure park | Botanic gardens | Wildlife centre | Red castle | Total | |---|---|---|---|---|---| | Boys | 65 | 12 | | 36 | | | Girls | | 9 | 62 | | 163 | | Staff | 15 | 3 | | | 37 | | Total | 144 | 24 | 121 | 71...See it on the paper →

What examiners said

Many candidates attempted factorisation, as required, although a substantial number solved the equation using the quadratic formula and were not awarded method marks. Where factorisation was attempted, this was usually done correctly although in some cases candidates produced factors such as (2x – 10) (x + 10.5). Some gave partial factors, usually 2x (x – 5) + 21(x – 5), as a first step, and gener...

— Examiner report, May/June 2023, 0980/42 Q3(a)(ii) (Cambridge)

Only the most able candidates could equate their expression with the given expression and then solve correctly. Some candidates who were unable to get to the correct answer could often equate the expressions for the two companies and start to rearrange them. Some simply added the two expressions. There were many attempts to use simultaneous equations by equating both expressions to y, but these at...

— Examiner report, October/November 2021, 0980/31 Q3(d)(ii) (Cambridge)