0580.C1.3.01 — Calculate with the following: squares.: past paper questions

Real questions on 0580.c1.3.01 — calculate with the following: squares.

The newest 12 of 12 written questions. Open one to see it on the real paper.

1. 0980/22 · May/June 2025 · Q7a[1]
   7 These are the first 4 terms of a sequence. 11 8 5 2 (a) Find the next term of this sequence.See it on the paper →
2. 0980/22 · May/June 2025 · Q7b[2]
   7 These are the first 4 terms of a sequence. 11 8 5 2 (b) Find the $n$th term of this sequence.See it on the paper →
3. 0980/21 · October/November 2024 · Q1[1]
   1 A concert starts at 1950 and finishes 2 hours 42 minutes later. Work out the time the concert finishes.See it on the paper →
4. 0980/31 · October/November 2024 · Q8b(i)[2]
   (b) (i) Complete the table of values for $y=2x^2+x$. | $x$ | 0 | 1 | 2 | 3 | 4 | 5 | | :--- | :--- | :--- | :--- | :--- | :--- | :--- | | $y$ | 0 | 3 | 10 | | | |See it on the paper →
5. 0980/32 · May/June 2024 · Q1b(iv)[1]
   (b) Find the value of (iv) $36^{\frac{1}{2}}$.See it on the paper →
6. 0980/32 · May/June 2024 · Q2b[2]
   (b) Find the value of $c^2+d^2$ when $c=7$ and $d=-5$.See it on the paper →
7. 0980/32 · May/June 2024 · Q6a(i)[3]
   Complete the table of values for $y=-x^2+8x+1$. | $x$ | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | | :--- | :--- | :--- | :--- | :--- | :--- | :--- | :--- | :--- | :--- | | $y$ | | | 13 | | 17 | | 13 | | 1 |See it on the paper →
8. 0980/32 · May/June 2024 · Q8e[2]
   The diagram shows a plan, $ABCDE$, of the floor of a room in Jo’s house. $F$ is a point inside the room. [Diagram: A polygon $ABCDE$ with right angles at $B$, $C$, $D$, and $E$. $AB$ is horizontal with length $3.6\text{ m}$. $BC$ is vertical with length $4.7\text{ m}$. $CD$ is horizontal with length $5.5\text{ m}$. $DE...See it on the paper →
9. 0980/31 · October/November 2023 · Q10b[3]
   (b) $ABC$ is a right-angled triangle. [Diagram: A right-angled triangle $ABC$ with the right angle at $B$. Side $AB$ is vertical with length $3.5\text{ cm}$. Side $AC$ is the hypotenuse with length $9.1\text{ cm}$. Side $BC$ is horizontal. The diagram is marked "NOT TO SCALE".] Calculate $BC$.See it on the paper →
10. 0980/41 · October/November 2023 · Q2a[2]
    2 (a) $s=\frac{1}{2}a{t}^2$ Find the value of $s$ when $a=9.8$ and $t=20.$See it on the paper →
11. 0980/31 · October/November 2021 · Q8a(i)[2]
    The diagram shows a right-angled triangle, $ABC$. [Diagram: A right-angled triangle $ABC$ with the right angle at $C$. The side $AB$ is labelled $125\text{ m}$ and the side $AC$ is labelled $100\text{ m}$. The text "NOT TO SCALE" is present.] (i) Show that $BC=75\text{ m}$.See it on the paper →
12. 0980/32 · May/June 2021 · Q6b[2]
    [Diagram: A quadrilateral $PQRS$ not to scale. $P$ is top-left, $Q$ is top-right, $R$ is bottom-right, $S$ is bottom-left. Side $PQ$ is horizontal with length $98\text{ m}$. Side $QR$ is vertical with length $67\text{ m}$. There is a right-angle symbol at vertex $Q$.] The diagram shows a field $PQRS$. $PQ = 98\text{ m}...See it on the paper →

What examiners said

Almost all candidates found the next term correctly. Most of those who scored the mark showed how they obtained the common differences, which they used to obtain the next term in the sequence. A few found a term before the start of the sequence, using 11 + 3 to give a wrong answer of 14, and some added 3 to give an answer of 5. A small minority also gave the nth term instead of the next term, but...

— Examiner report, May/June 2025, 0980/22 Q7(a) (Cambridge)

Candidates who simply wrote down their answer from the term-to-term difference and the ‘zero term’ mostly gave the correct answer. The method used for finding the common difference was clear, however some candidates made the error of using the common difference as 3 instead of –3, which led to answers of 3n + 14 or 3n – 8. Those who used the formula a + (n – 1)d were more likely to make mistakes,...

— Examiner report, May/June 2025, 0980/22 Q7(b) (Cambridge)

The incorrect answer of 24 was more common than the correct answer of 74. This arose from wrongly calculating (–5)2 as - (52). Those that showed their working generally gained a method mark for 49 whilst those showing no working mostly scored 0. This part was also answered very well. There were different approaches with some candidates divided 360 by 12 to find the exterior angle first before subt...

— Examiner report, May/June 2024, 0980/32 Q2(b) (Cambridge)