[Diagram: A quadrilateral ABCD with diagonal BD. AB=10 cm, AD=14 cm. Angle DAB=65∘. Angle CBD=75∘. Tick marks indicate BC=CD. Label "NOT TO SCALE".]
Triangle BCD is isosceles.
(c) Find the perimeter of ABCD.See it on the paper →
0607/42 · February/March 2025 · Q15a[1]
[Diagram: A circle with centre O. Points A and C are on the circle. Lines BA and BC are tangents to the circle at A and C respectively, meeting at point B. The radius OA is labelled 4 cm. The angle ∠AOC is labelled 154∘. The region bounded by the arc AC and the chord AC is...See it on the paper →
0607/62 · February/March 2025 · Q1a[1]
The diagram shows a square and 2 regular octagons fitting together at a point.
[Diagram: A square positioned between two regular octagons, all meeting at a central point.]
This is the formula for the size of each interior angle, a∘, of a regular polygon with n sides.
a=180−n360
(a) Show that t...See it on the paper →
0607/62 · February/March 2025 · Q1b[2]
The diagram shows a square and 2 regular octagons fitting together at a point.
[Diagram: A square positioned between two regular octagons, all meeting at a central point.]
This is the formula for the size of each interior angle, a∘, of a regular polygon with n sides.
a=180−n360
(b) Use angles...See it on the paper →
0607/12 · February/March 2023 · Q16[2]
16 Work out the size of one exterior angle of a regular 10-sided polygon.See it on the paper →
0607/12 · May/June 2019 · Q4[2]
2-mark “Draw” question — its maths and diagrams are best seen on the paper.
Most realised the lengths required to work out the perimeter and many successfully reached the correct answer. Various methods were used to calculate the length of BC. Most used the sine rule or the cosine rule and some right-angle triangle trigonometry with the bisector of angle BDC. A few, having worked out the required lengths correctly, added the length BD in with the other four lengths. A sma...