0653.P1.5.01 — Know that forces may produce changes in 7 Recall and use the equation the size, shape and motion of an object F = ma and know that the resul: past paper questions
Real questions on 0653.p1.5.01 — know that forces may produce changes in 7 recall and use the equation the size, shape and motion of an object f = ma and know that the resul
The newest 20 of 39 written questions. Open one to see it on the real paper.
- 0653/06 · Specimen 2025 · Q4bi[1]
Calculate the distance x1 from the centre of the load to the pivot.
See it on the paper → - 0653/06 · Specimen 2025 · Q4bii[1]
Calculate the distance x2 from the centre of the load to the pivot.
See it on the paper → - 0653/06 · Specimen 2025 · Q4biii[1]
Use the results for (b)(i) and (b)(ii) to calculate the mass M of the metre rule. Use the equation shown. M = 5 (x1 + x2)
See it on the paper → - 0653/06 · Specimen 2025 · Q4ci[1]
State the name of the apparatus shown in Fig. 4.4.
See it on the paper → - 0653/32 · May/June 2025 · Q7a(ii)[1]
Calculate the resultant force acting on the tram. resultant force = N
See it on the paper → - 0653/41 · May/June 2025 · Q7c[3]
Calculate the resultant force acting on the car. Include the unit in your answer. force = unit
See it on the paper → - 0653/42 · May/June 2025 · Q7a(i)[1]
State which force, P, Q, R or S, is the driving force.
See it on the paper → - 0653/42 · May/June 2025 · Q7a(ii)[1]
Explain why forces Q and S must be balanced.
See it on the paper → - 0653/42 · May/June 2025 · Q7b(i)[3]
Calculate the resultant force acting on the tram. force = unit Include the unit in your answer.
See it on the paper → - 0653/42 · May/June 2025 · Q7b(ii)[2]
Calculate the increase in speed of the tram. increase in speed = m / s
See it on the paper → - 0653/42 · May/June 2025 · Q7b(iii)[3]
Calculate the power required for this increase in speed. power = W
See it on the paper → - 0653/43 · May/June 2025 · Q7b(i)[2]
Calculate the resultant force acting on the car. force = N
See it on the paper → - 0653/62 · February/March 2025 · Q4c(i)[2]
Calculate the force F exerted by the wooden block on the table. Use your answer in (b) and the equation shown. F = m × 9.8 1000 Give your answer to two significant figures. F = N (c) (i)
See it on the paper → - 0653/62 · February/March 2025 · Q4c(ii)[1]
State the name of a piece of apparatus that measures F directly.
See it on the paper → - 0653/32 · October/November 2024 · Q6c[2]
The horse pulls the cart forward with constant force F. Fig. 6.2 shows force F acting on the cart. F Fig. 6.2 Force F keeps the cart moving at constant speed. Suggest why force F does not increase the speed of the cart.
See it on the paper → - 0653/32 · October/November 2024 · Q9a(i)[1]
On Fig. 9.1, draw and label a force arrow to show the weight of the candle.
See it on the paper → - 0653/32 · October/November 2024 · Q9a(ii)[3]
The mass of the candle is 12 g. The gravitational force on unit mass is 10 N / kg. weight = N Calculate the weight of the candle.
See it on the paper → - 0653/33 · October/November 2024 · Q6c[2]
The horse pulls the cart forward with constant force F. Fig. 6.2 shows force F acting on the cart. F Fig. 6.2 Force F keeps the cart moving at constant speed. Suggest why force F does not increase the speed of the cart.
See it on the paper → - 0653/33 · May/June 2024 · Q3b(i)[1]
Explain why force S must also be 2500 N as the bus moves along a level road at constant speed.
See it on the paper → - 0653/33 · May/June 2024 · Q3b(ii)[1]
Force Q is increased to 3000 N. Force S does not change. Find the resultant of the forces Q and S acting on the bus. resultant = N
See it on the paper →
What examiners said
Since forces P and Q were not of the same magnitude there was a resultant force of 500 N. The main mistake, made by a minority of candidates, was adding the two forces together, getting 4300 N instead of calculating the difference between P and Q. Candidates should be aware that the arrows indicate the direction in which the forces are acting. P and Q are acting in opposite directions, so they go...
— Examiner report, May/June 2025, 0653/32 Q7(a)(ii) (Cambridge)
The relationship force = mass x acceleration was familiar to many candidates and full credit was often awarded. Either 4.5 or 5 or the value of acceleration calculated in 7(b) were accepted in this calculation. Although some candidates could not make any progress with the calculation, they often gained credit for stating the units. The equivalent units, kg m s-2 and correct variations were accepte...
— Examiner report, May/June 2025, 0653/41 Q7(c) (Cambridge)
Almost all candidates identified the label of the driving force in the diagram of a moving tram.
— Examiner report, May/June 2025, 0653/42 Q7(a)(i) (Cambridge)
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