0654.P1.6.05 — Recall and use the equation for kinetic energy Ek = 12 mv 2: past paper questions
Real questions on 0654.p1.6.05 — recall and use the equation for kinetic energy ek = 12 mv 2
The newest 5 of 5 written questions. Open one to see it on the real paper.
- 0654/33 · May/June 2025 · Q12a(iii)[2]
The current in component Z is 0.50 A. resistance = Ω Calculate the resistance of component Z. The voltage supplied by component X is 1.5 V.
See it on the paper → - 0654/43 · May/June 2025 · Q9c(ii)[2]
Before the crash, the car has a velocity of 28 m / s. The kinetic energy of the car is 470 kJ. Calculate the mass of the car. mass = kg
See it on the paper → - 0654/22 · May/June 2022 · Q30[1]
What is the speed of the object when its kinetic energy is 4.0 E ?
See it on the paper → - 0654/21 · May/June 2021 · Q31[1]
Which form of energy is increasing as he accelerates downwards through the air?
See it on the paper → - 0654/21 · May/June 2019 · Q29[1]
Which object has kinetic energy equal to that of object X?
See it on the paper →
What examiners said
The equation for resistance was one of the better-known relationships and those who correctly applied it were able to complete the calculation. Candidates should take care to record their answers to the appropriate number of significant figures (shown by the number used in the question) meaning an answer of 3.0 was most appropriate here.
— Examiner report, May/June 2025, 0654/33 Q12(a)(iii) (Cambridge)
Candidates found this demanding. Some gave the expression for kinetic energy but could not rearrange it and evaluate the answer. Some attempted to use F = ma.
— Examiner report, May/June 2025, 0654/43 Q9(c)(ii) (Cambridge)
The most common error here was to overlook the fact that kinetic energy depends on the square of the speed, therefore arriving at option C.
— Examiner report, May/June 2022, 0654/22 Q30 (Cambridge)
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