0654.P4.2.02 — Recall and use the equation for resistance 3 Sketch and explain the current–voltage graph V of a resistor of constant resistance R= I: past paper questions
Real questions on 0654.p4.2.02 — recall and use the equation for resistance 3 sketch and explain the current–voltage graph v of a resistor of constant resistance r= i
The newest 20 of 35 written questions. Open one to see it on the real paper.
- 0973/41 · May/June 2026 · Q10b(iii)[1]
The heater is a resistor. On Figure 10.1, sketch the current-voltage graph for a resistor of constant resistance. current A 0 > 0) voltage Figure 10.1
See it on the paper → - 0973/42 · May/June 2026 · Q11a(i)[1]
11 (a) (i) State the change in the resistance of a metal wire when the length of the wire doubles.
See it on the paper → - 0973/42 · May/June 2026 · Q11a(ii)[1]
(ii) Wire A has a length of 45m and a resistance of 12.6Q. Wire B is made of the same metal as wire A and has a length of 45m. Wire B has twice the cross-sectional area of wire A. Determine the resistance of wire B. resistance Wire .......... [1]
See it on the paper → - 0973/42 · May/June 2026 · Q11b(ii)[2]
(ii) Calculate the current at point X in the circuit. Use your answer to 11(b)(i). CUITONE .......... [2]
See it on the paper → - 0973/31 · October/November 2025 · Q12c(ii)[2]
The water in the washing machine is heated by a heating element. A current of 3.0 A passes through the heating element when the voltage across the heating element is 230 V. Calculate the resistance of the heating element. resistance = Ω
See it on the paper → - 0973/32 · May/June 2025 · Q12a(iii)[2]
The current in component Z is 0.50 A. resistance = Ω Calculate the resistance of component Z. The voltage supplied by component X is 1.5 V.
See it on the paper → - 0973/31 · October/November 2024 · Q9c(i)[2]
There is a potential difference (p.d.) of 240 V across the ultraviolet lamp. There is a current of 0.75 A in the ultraviolet lamp. Calculate the resistance of the ultraviolet lamp. resistance = Ω
See it on the paper → - 0973/41 · October/November 2024 · Q3b(ii)[2]
The ammeter reads 0.60 A. Use your answer to (b)(i) to calculate the resistance of the cylinder of graphite. resistance = Ω
See it on the paper → - 0973/41 · October/November 2024 · Q3b(iii)[2]
A different cylinder of graphite has double the length and double the cross‑sectional area of the cylinder in Fig. 3.2. Explain why the resistance of both cylinders is the same.
See it on the paper → - 0973/31 · May/June 2024 · Q3a(iv)[2]
Use information from Fig. 3.2 to calculate the resistance of the lamp when lit. resistance = Ω
See it on the paper → - 0973/32 · May/June 2024 · Q12b[2]
The lamp in Fig. 12.1 has a current of 0.40 A in it when the potential difference across it is 3.0 V. Calculate the resistance of the lamp. resistance = Ω
See it on the paper → - 0973/31 · October/November 2023 · Q6b(i)[2]
Calculate the potential difference across lamp A. potential difference = V
See it on the paper → - 0973/31 · October/November 2023 · Q6b(ii)[1]
Calculate the combined resistance of the two lamps connected in series. resistance = Ω
See it on the paper → - 0973/31 · October/November 2023 · Q6b(iii)[2]
The two lamps are now connected in parallel. Their combined resistance is different. Fig. 6.2 Identify from the list the combined resistance of the two lamps connected in parallel. Explain your answer. 2.4 Ω 4.0 Ω 6.0 Ω 10 Ω 24 Ω combined resistance explanation
See it on the paper → - 0973/32 · May/June 2023 · Q9b[3]
Lamp X has a resistance of 2 Ω and lamp Y has a resistance of 4 Ω. Calculate the potential difference across lamp Y. State the unit of your answer. potential difference = unit
See it on the paper → - 0973/41 · May/June 2023 · Q9a[2]
The student moves the crocodile clips to change the length of the wire. She measures this length with the ruler and uses the ammeter reading to calculate the resistance of the wire. When the wire is made longer, the reading on the ammeter decreases. Explain why the reading on the ammeter decreases.
See it on the paper → - 0973/41 · May/June 2023 · Q9b(ii)[2]
The student uses the component labelled X to vary the potential difference across the length of wire. The student records the potential difference across the wire and the current in the wire. Fig. 9.3 shows her results. 1.75 1.50 1.25 1.00 potential difference / V 0.75 0.50 0.25 0 0 0.20 0.40 current / A Fig. 9.3 0.60...
See it on the paper → - 0973/42 · May/June 2023 · Q9a(i)[1]
Determine the potential difference shown on the voltmeter. potential difference = V
See it on the paper → - 0973/42 · May/June 2023 · Q9b[3]
Fig. 9.2 shows the second circuit made by the student using the same three identical filament lamps. 6.0 V A A V Fig. 9.2 0.9 A One of the ammeters shows a current of 0.9 A as shown in Fig. 9.2. The voltmeter shows a potential difference of 6.0 V. Calculate the resistance of one of the filament lamps. resistance = Ω
See it on the paper → - 0973/31 · October/November 2022 · Q9a(ii)[3]
The current passing through each lamp is 4.0 A. The potential difference across each lamp is 12 V. Calculate the resistance of each lamp. State the unit of your answer. resistance = unit
See it on the paper →
What examiners said
The equation for resistance was one of the better-known relationships and those who correctly applied it were able to complete the calculation. Candidates should take care to record their answers to the appropriate number of significant figures (shown by the number used in the question) meaning an answer of 3.0 was most appropriate here.
— Examiner report, May/June 2025, 0973/32 Q12(a)(iii) (Cambridge)
Many candidates explained the correct relationship between resistance and current and were able to explain why the ammeter reading decreased.
— Examiner report, May/June 2023, 0973/41 Q9(a) (Cambridge)
The resistance of the wire calculation was carried out very well by almost all candidates. Occasionally the equation was inverted.
— Examiner report, May/June 2023, 0973/41 Q9(b)(ii) (Cambridge)
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