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See it on the paper →Comprehensive responses • Many candidates calculated the cost per hour, using their value of v and the number of hours that the journey would take. There was a range of acceptable answers due to the different possible places where the candidates could have approximated their answers. Limited responses • Some candidates did not use 150 km in the correct context. • Some candidates calculated the c...
— Examiner report, February/March 2026, 0606/22 Q7(b) (Cambridge)
Many completely correct solutions were seen. The most common method and by far the simplest method was to equate the two given equations, form a quadratic equation equated to zero and then make use of the discriminant of this quadratic equation. Other methods included equating gradients and substitution of the resulting relationship into an appropriate equation to either the value of k, or the val...
— Examiner report, February/March 2020, 0606/12 Q2 (Cambridge)
A good number of candidates earned at least six of the eight marks available for this question. The overwhelming majority of candidates used the information given about the volume of the cylinder to write h as an expression in r. A good number of these candidates formed a correct expression for the surface area and went on to differentiate and solve correctly. Some candidates included both ends of...
— Examiner report, February/March 2020, 0606/22 Q11 (Cambridge)
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