0606.14.5: Use differentiation to find gradients, tangents and normals: past paper questions
81 real questionsasked in 9 of the last 10 exam series2019–2026usually: Find, Show, Use, Write
Real questions on 0606.14.5: use differentiation to find gradients, tangents and normals
The newest 20 of 81 written questions. Open one to see it on the real paper.
0606/12 · May/June 2026 · Q5[4]
Find, in exact form, the equation of the tangent to the curve y=ln((2x−4)5) at the point where x=3.See it on the paper →
0606/13 · May/June 2026 · Q6b[4]
In this question time is in seconds and lengths are in centimetres.
You are given that cos30∘=23, sin30∘=21 and tan30∘=31.
A water tank is shaped as a cone with its axis vertical.
The angle between the vertical axis and the sloping edge of the co...See it on the paper →
0606/13 · May/June 2026 · Q12a[2]
A curve has equation y=ex2a where a is a positive constant.
(a) Find dxdy in terms of a.See it on the paper →
0606/13 · May/June 2026 · Q12b[5]
12 A curve has equation y=ex2a where a is a positive constant.
(b) Find the value of a.See it on the paper →
0606/21 · May/June 2026 · Q10[10]
10 A curve has equation y=x2ln(3x2+5).
The normal to the curve at the point where x=−1 meets the x-axis at the point P and the y-axis at the point Q.
Find the area of the triangle OPQ, where O is the origin.
Give your answer correct to 3 significant figures.See it on the paper →
0606/22 · May/June 2026 · Q12[4]
12 A sphere has volume V cm3 and radius r cm.
Given that r varies with time t, find V at the instant when dtdV=9dtdrSee it on the paper →
0606/12 · February/March 2026 · Q3b[1]
In this question, time t is in seconds and displacement s is in metres.
A particle starts from rest at the origin O and moves in a straight line with constant positive acceleration.
When t=4, s=6.
(b) Hence find the acceleration.See it on the paper →
0606/12 · February/March 2026 · Q8b[5]
A curve has equation y=xe2x+1.
(b) The line L is the tangent to the curve at the point where x=21.
Find the exact coordinates of the two points where L meets the axes.See it on the paper →
0606/12 · October/November 2025 · Q4b[2]
A function f is such that f(x)=2x2+5x+3, for x⩾p, where p is a constant.
It is given that f−1 exists.
(b) Hence write down the coordinates of the stationary point on the curve y=2x2+5x+3.See it on the paper →
5 The normal to the curve y=x3+23x2−2x+1 at the point where x=0 cuts the curve again at two other points.
Find the x-coordinates of these two points.See it on the paper →
0606/11 · May/June 2025 · Q6b(i)[1]
6 A curve has equation y=(x2+1x2−1)4.
(b) (i) Show that the curve has stationary points where x=−1, x=0 and x=1.See it on the paper →
0606/12 · May/June 2025 · Q8a[5]
It is given that y=x+2ln(3x2+16).
(a) Find dxdy when x=0.
Give your answer in the form lnp, where p is a constant.See it on the paper →
0606/21 · May/June 2025 · Q10a(i)[3]
A particle P moves in a straight line.
t seconds after passing a fixed point, O, the acceleration of P, a ms−2, is given by
a=t2−2for 0≤t≤4a=19−5e8−2tfor 4≤t≤10.
When t=3, the velocity of P is $\frac{1}{3} \text{ ms}^{-...See it on the paper →
0606/22 · May/June 2025 · Q4b[5]
(b) A curve has equation y=4sin2xcos2x.
The normal to the curve at the point where x=6π meets the x-axis at the point P.
Find the exact coordinates of P.See it on the paper →
0606/12 · February/March 2025 · Q10[9]
10 The point P lies on the curve y=(5x+2)32.
The x-coordinate of P is 5.
The normal to the curve at P intersects the line x+y=11 at the point Q.
The point R is the reflection of Q in the tangent to the curve at P.
Find the coordinates of R.See it on the paper →
0606/22 · February/March 2025 · Q2a[4]
(a) Find the x-coordinates of the stationary points on the curve y=21(3−2x)(x+2)2.See it on the paper →
0606/22 · February/March 2025 · Q6b[2]
It is given that y=x+2ln(2x2+1).
(b) Given that x increases from 2 to 2+h, where h is small, find the approximate change in y.See it on the paper →
0606/22 · February/March 2025 · Q9d[1]
In this question, all lengths are in metres and time is in seconds.
A particle, P, moves in a straight line such that t seconds after passing through a fixed point O its displacement, s, is given by s=5ln(2t+1)−5t.
(d) Find the acceleration when t=4.5.See it on the paper →
0606/22 · October/November 2024 · Q2b[3]
3-mark “Find” question — its maths and diagrams are best seen on the paper.
Comprehensive responses • Many candidates offered a correct solution for their linear velocity-time graph from part (a).
Limited responses • A few candidates who had drawn curves in part (a) were unable to offer a valid solution in this part as their graphs did not justify a constant acceleration. • A few candidates attempted to use suvat equations and sometimes this was done incorrectly. Knowled...
Fully correct responses showed that the denominator needed only to equal zero, then correctly deduced the three values of x by solving the resulting equations. Where verification was attempted, candidates often struggled to communicate clearly what they were attempting to show.
Most candidates attempted differentiation of a quotient, usually using the correct form. Some chose to use the differentiation of a product which was just as acceptable provided it was a correct ( ) product. Errors usually occurred with the incorrect differentiation of ln 3 x 2 + 16 . The form of the final answer was given, however some candidates did not simplify their correct work sufficiently a...