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See it on the paper →11-mark “Find” question — its maths and diagrams are best seen on the paper.
See it on the paper →Most candidates successfully identified y = 3, differentiated correctly, and formed a correct equation for the tangent. Those who obtained the correct equation were generally able to find the x-intercept. However, few candidates were successful in calculating the correct area of the triangle – whether by integration or by using 1 base height. Integration was generally well attempted, though some c...
— Examiner report, May/June 2025, 0606/11 Q9 (Cambridge)
The most straightforward method of solution was to find the area of the trapezium that could be formed and subtract the area under the curve. Some candidates made the problem more complex than necessary by finding the equation of the line AB first and then using subtraction and integration. Errors were more likely to occur using this method. Few completely correct solutions were seen due to errors...
— Examiner report, May/June 2025, 0606/13 Q8(b) (Cambridge)
This question part was probably one of the most demanding parts of the paper, with many candidates finding the value of s when t = 0 and the value of s when t = 2. Again, candidates were expected to consider the work done in part (a) which was meant to inform them that the particle was at rest in the time interval stated. Consideration of the value of s when t = 0.5 was also essential. Candidates...
— Examiner report, February/March 2025, 0606/22 Q9(b) (Cambridge)
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