0580.C4.1.10 — similar.: past paper questions

Real questions on 0580.c4.1.10 — similar.

The newest 20 of 27 written questions. Open one to see it on the real paper.

1. 0580/11 · May/June 2026 · Q4a[1]
   (a) Points $A$ and $B$ lie on a circle, centre $O$, as shown in the diagram. [Diagram: A circle with centre $O$. Points $A$ and $B$ are on the circumference. A straight line segment connects $A$ and $B$.] Write down the mathematical name for line $AB$.See it on the paper →
2. 0580/12 · May/June 2026 · Q17a[1]
   17 (a) Two of the angles in a triangle are $100^{\circ }$ and $30^{\circ }$. Work out the size of the third angle.See it on the paper →
3. 0580/12 · May/June 2026 · Q17b[2]
   (b) Work out the size of an interior angle of a regular 10-sided polygon.See it on the paper →
4. 0580/12 · May/June 2026 · Q19a[1]
   19 Line $L$ has the equation $y=3x+7$. (a) Write down the gradient of line $L$.See it on the paper →
5. 0580/21 · October/November 2025 · Q14a[2]
   [Diagram: A circle with points $A,B,C,D,E$ on its circumference. Chords $AC$ and $BD$ intersect at point $X$. Angle $ACD$ is marked as $55^{\circ }$. Angle $CXD$ is marked as $88^{\circ }$. The diagram is labeled "NOT TO SCALE".] $A,B,C,D$ and $E$ lie on the circle. $AC$ and $BD$ intersect at $X$. Angle $ACD = 55^\cir...See it on the paper →
6. 0580/22 · October/November 2025 · Q11a[3]
   [Diagram: A triangle $PQR$ with vertex $P$ at the top, $Q$ at the bottom left, and $R$ at the bottom right. A line segment $ST$ is drawn inside the triangle, parallel to the base $QR$, with $S$ on side $PQ$ and $T$ on side $PR$. Arrows on $ST$ and $QR$ indicate they are parallel. The text "NOT TO SCALE" is written to t...See it on the paper →
7. 0580/43 · October/November 2025 · Q22a[2]
   [Diagram: Two mathematically similar triangles. The smaller triangle has a side of $14\text{ mm}$ and a side of $10\text{ mm}$ adjacent to a marked angle. The larger triangle has a corresponding side of $x\text{ mm}$ and a side of $45\text{ mm}$ adjacent to the corresponding marked angle. The text "NOT TO SCALE" is pre...See it on the paper →
8. 0580/43 · October/November 2025 · Q22b[3]
   (b) The surface areas of two mathematically similar containers are $124{\text{ cm}}^2$ and $279{\text{ cm}}^2$. The capacity of the smaller container is $56\text{ ml}$. Find the capacity of the larger container.See it on the paper →
9. 0580/43 · October/November 2025 · Q24a[3]
   The diagram shows a cuboid $ABCDEFGH$. $AE=6.4\text{ cm}$, $EH=5.1\text{ cm}$ and $AG=13\text{ cm}$. [Diagram: A cuboid $ABCDEFGH$ with vertices labelled. $AE$ is a vertical edge of length $6.4\text{ cm}$. $EH$ is a horizontal edge of length $5.1\text{ cm}$. $AG$ is a space diagonal of length $13\text{ cm}$...See it on the paper →
10. 0580/43 · October/November 2025 · Q24b[3]
    The diagram shows a cuboid $ABCDEFGH$. $AE=6.4\text{ cm}$, $EH=5.1\text{ cm}$ and $AG=13\text{ cm}$. [Diagram: A cuboid $ABCDEFGH$ with $AE=6.4\text{ cm}$, $EH=5.1\text{ cm}$, and a dashed line $AG=13\text{ cm}$.] (b) Calculate the angle between the line $AG$ and the base $EFGH$ of the cuboid.See it on the paper →
11. 0580/43 · October/November 2025 · Q26b[2]
    [Diagram: A parallelogram $ABCD$ with vertices labeled counterclockwise starting from bottom-left. Vector $\overrightarrow{AB}$ is labeled $\mathbf{m}$. Vector $\overrightarrow{AD}$ is labeled $\mathbf{p}$. Point $F$ is on side $BC$. Point $E$ is on side $AD$. A line segment connects $E$ and $F$. The diagram is marked...See it on the paper →
12. 0580/13 · May/June 2025 · Q18a[2]

    2-mark “Find” question — its maths and diagrams are best seen on the paper.

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13. 0580/13 · May/June 2025 · Q18b[3]

    3-mark “Find” question — its maths and diagrams are best seen on the paper.

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14. 0580/13 · May/June 2025 · Q19[2]

    2-mark “Calculate” question — its maths and diagrams are best seen on the paper.

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15. 0580/23 · May/June 2025 · Q2[4]
    2 [Diagram: A quadrilateral $ABCD$ with a triangle $AFB$ attached to side $AB$. $CDE$ is a straight line. Angle $CDE$ is $104^{\circ }$. Angle $BCD$ is $70^{\circ }$. Angle $ABC$ is $130^{\circ }$. Angle $DAB$ is $x^{\circ }$. Angle $BAF$ is $30^{\circ }$. Angle $AFB$ is $y^{\circ }$. Sides $AF$ and $FB$ are marked as equal.] $ABCD$ is...See it on the paper →
16. 0580/31 · May/June 2025 · Q24[2]
    [Diagram: Two triangles, $ABC$ and $UVW$, NOT TO SCALE. Triangle $ABC$ has side $AC=12$ cm. Triangle $UVW$ has side $UV=14$ cm and side $UW=21$ cm.] Triangle $ABC$ is mathematically similar to triangle $UVW$. Calculate $AB$.See it on the paper →
17. 0580/21 · May/June 2024 · Q6[3]
    [Diagram: A chain of 5 congruent kites joined at a common vertex $C$. The first kite is $ABCD$ with $\angle DAB=40^{\circ }$. The kites are arranged in a fan shape. The last kite has an angle labelled $x^{\circ }$ at vertex $C$. The line $DCE$ is a straight line. NOT TO SCALE.] The diagram shows 5 kites that are congruent...See it on the paper →
18. 0580/13 · October/November 2023 · Q1[1]

    1-mark “Write down” question — its maths and diagrams are best seen on the paper.

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19. 0580/12 · May/June 2023 · Q3[2]

    2-mark “Shade” question — its maths and diagrams are best seen on the paper.

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20. 0580/12 · February/March 2023 · Q12[2]
    12 Work out the size of one interior angle of a regular 9-sided polygon.See it on the paper →

What examiners said

The value of the angle was correctly found by most candidates, although giving sufficient reason was challenging and very few candidates were awarded two marks.

— Examiner report, May/June 2025, 0580/13 Q18(a) (Cambridge)

This was generally well answered. Finding and indicating the 90⁰ angle on the diagram gained a mark for many candidates who found this question difficult, often candidates went on to find ORS and the value of y. It was more common to get the B1 for OSR than ROS. There were arithmetic errors when adding or subtracting angles. 155 was a common incorrect answer from 180 – 25.

— Examiner report, May/June 2025, 0580/13 Q18(b) (Cambridge)

This question was not well done overall. Candidates who knew the correct formula for the sector of a circle were able to substitute correctly and gain a method mark, several who had done this did not evaluate it correctly. Some worked out the area of a full circle, others tried to use a numerical value for π despite not having a calculator.

— Examiner report, May/June 2025, 0580/13 Q19 (Cambridge)